Comments for Innovative Thought

Comment on Simulating a Table Using an Unordered List by E-sitesweb » 45 Powerful CSS/JavaScript-Techniques

E-sitesweb » 45 Powerful CSS/JavaScript-Techniques — Wed, 28 Dec 2011 12:01:44 +0000

[...] Simulating a Table Using an Unordered List Your first question immediately might be, “why would I want to simulate a table with a list, why not just use a table?” With the raise in popularity of AJAX sortable list elements, using list items to represent a multiple column data table can allow for easy sorting of various more “tabley” information. So let’s get started. [...]

Comment on Simulating a Table Using an Unordered List by Lee Taylor

Lee Taylor — Thu, 17 Nov 2011 01:20:25 +0000

What an extraordinary piece of software!! Well conceived.

Have created a “css” file with 5 columns, …_col1 thru …_col5, each 18% as it needs to be < 100% due to borders, inside a "wrapper" of whatever width. Can now in the "html" page, make it scalable from 1 to 5 columns, modifying the width %.

Am in the process of rewriting my current website using "Tabs" & now incorporating "your" CSS Table!!!

Thanks for the gift.

Lee

Comment on Simulating a Table Using an Unordered List by 45 Powerful CSS/JavaScript-Techniques « DownGraf – Design weblog for designers

Wed, 29 Jun 2011 06:43:51 +0000

Comment on Resetting Your Forgotten MySQL Password by madhavi ganti

madhavi ganti — Mon, 13 Jun 2011 20:43:48 +0000

Thanks !! That worked :)

Comment on Resetting Your Forgotten MySQL Password by Tim Knight

Tim Knight — Mon, 13 Jun 2011 12:39:50 +0000

First make sure that you have the server running successfully without the grant tables. Next you might consider running the server using the sudo command if you didn’t previously. There are several entries in the MySQL support forum with that error message that might be able to provide you with some solid insight.

Comment on Resetting Your Forgotten MySQL Password by madhavi ganti

madhavi ganti — Mon, 13 Jun 2011 04:04:59 +0000

On opening the second terminal window, and using ” /usr/local/mysql/bin/mysql mysql” (withouth quotes) resulted in ERROR 1044 (42000): Access denied for user ”@’localhost’ to database ‘mysql’…Any ideas how I can resolve this?? :(

Comment on Making Configuration Files with YAML: Revised by Tim Knight

Tim Knight — Wed, 01 Jun 2011 12:18:40 +0000

Thanks Peter. Yes you can reference other settings by setting there name with &name. You can see that in use where I’m importing all of the development settings into the test environment. You pointed out however that you can set individual items as well—thanks for digging into more details on the concept.

Comment on Making Configuration Files with YAML: Revised by Peter Nixey

Peter Nixey — Wed, 01 Jun 2011 10:41:29 +0000

This is really useful thank you. After looking at this I wondered how you could DRY the config file up and discovered that you can use ‘anchors’ and ‘references’ to do this.
(http://en.wikipedia.org/wiki/YAML#Language_elements)

For instance, if the site title is the same in development as test and production then you can define it as follows:

development:
site_title: &title My new website

test:
site_title: *title

production
site_title: *title

Thanks for the post and hope this is helpful :)

Comment on Making Configuration Files with YAML: Revised by Pritesh

Pritesh — Mon, 16 May 2011 17:48:05 +0000

cool…I am newbie to RoR and this article made my day , was looking for somthing like this to make the code look simple and flexible… thanks a lot Tim !

Comment on Formatting Names Using Ruby by Tim Knight

Tim Knight — Tue, 19 Apr 2011 13:54:46 +0000

That’s a great link, thank you for sharing. I always find it obnoxious when a system doesn’t properly take an apostrophe. As for your example of “van Campen” I have to say “it depends”. If the system most understand the difference between the first name and last name splitting the name programmatically wouldn’t be my approach. If I was going to do something I would still split it into an array. Move the first one out into the first name and then in what was remaining check to see if the next item in the array was “van” and if so include it with the last item in the array as the last name. I’m sure there is a better way, but that’s my initial thought.