Cleaning up my Ruby Fizzbuzz

As I become more familiar with Ruby and Rails I’m of course going to start to understand better ways to do a snippet of code. Here is an updated script that is a little leaner:

(1..100).each do |i|
  fb = []
  fb << "Fizz" if (i % 3) == 0
  fb << "Buzz" if (i % 5) == 0
  fb << i if (i % 3) != 0 and (i % 5) != 0
  puts (fb.join "")
end

I am still tring to review my notes, so I just ask that those of you awaiting my review of the Web 2.0 Expo please continue to be patient.

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Solving the Fizzbuzz Puzzle with Ruby

So back in February Jeff Atwood over at codinghorror.com was talking about a puzzle to give prospective new-hires when interviewing them entitled “Fizzbuzz”. You can read more about it here.

So with a little thought I decided to solve the fizzbuzz puzzle using Rudy and an Array.

count = 0
100.times do
  count += 1
  fb = []
  fb << "Fizz" if (count % 3) == 0
  fb << "Buzz" if (count % 5) == 0
  fb << count if (count % 3) != 0 and (count % 5) != 0
  puts (fb.join "")
end

For those of you that are curious as to why I used a local variable of count rather then the index identifier, is because the article by Jeff Atwood requests a loop from 1-100 and Ruby starts looping at 0.